A car moves in a circle at the constant speed of 50m/s and completes one revolution in 40s. Determine the magnitude of the acceleration of the car

ByManoj Jaiswar

As per the given situation,

v= 50m/s , T=40s , a= ?

a = v x (2π / T ) 

a = 50 x (2 x 3.142 / 40 )

a = 50 x 0.1571 = 7.855 m/s²

Similar Posts

As we go from one planet to another planet, how will the mass and weight of a body change?

ByManoj Jaiswar

Mass of any body is the quantity of matter contained in a given volume of the body. As we will go from one planet to another planet, the mass of a body i.e the content inside the body remains same. Hence the mass will remain constant. However as we have gone to the other planet ,so there…

Elastic and inelastic collision and their characteristics

ByManoj Jaiswar

Elastic collision : A collision in which both the momentum and kinetic energy of the body remains conserved. e.g. the collision between two metal balls. The basic characteristics of an elastic collision are ♦️Momentum is conserved.♦️Total energy is conserved.♦️Kinetic energy is conserved.♦️Forces involved in the interaction are of conservative nature.♦️Mechanical energy is not transformed into…

An echo-sounder in a fishing boat receives an echo from a shoal of fish 0.45 s after it was sent. If the speed of sound in water is 1500 m/s, how deep is the shoal?

ByManoj Jaiswar

Going through the sums, we can list the given quantities as, speed v= 1500 m/s time in which the signal is recieved back after hitting the shoal, i.e time for going+time for coming back i.e 2t = 0.45 s  therefore t = 0.225s To find distance d = ? Solution –  velocity, distance and time can be…

An ideal gas is taken through an isothermal process. If it does 2000 J of work on its environment, how much heat is added to it?

ByManoj Jaiswar

After going through the question, we can list some data as, workdone dW = 2000J isothermal process dU = 0 To find , Heat added dQ = ? Solution –  From first law of thermodynamics we have dQ = dU + dW In the question it is given that the gas is taken through isothermal…

A wave of frequency 500 Hz is travelling with a speed of 350 m/s. (a) What is the phase difference between two displacements at a certain point at times 1.0 ms apart? (b) what will be the smallest distance between two points which are 45º out of phase at an instant of time?

ByManoj Jaiswar

The given that can be listed is  frequency n = 500Hz speed v = 350m/s we can find wavelength λ  λ = v/n = 350/500 = 0.7m and time period T as T = 1/n = 1/500 = 0.002s = 2ms a) for a time difference of 1.0ms, phase difference ∆Φ = ?  for a phase…

Leave a Reply

Your email address will not be published. Required fields are marked *